Chemistry: What's Hot Now: Henry's Law Example

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Henry's Law Example Aug 9th 2011, 10:03 This example problem demonstrates how to use Henry's Law to calculate the concentration of a gas in solution under pressure. Problem: How many grams of carbon dioxide gas is dissolved in a 1 L bottle of carbonated water if the manufacturer uses a pressure of 2.4 atm in the bottling process at 25 °C? Given: KH of CO2 in water = 29.76 atm/(mol/L) at 25 °C Solution When a gas is dissolved in a liquid, the concentrations will eventually reach equilibrium between the source of the gas and the solution. Henry's Law shows the concentration of a solute gas in a solution is directly proportional to the partial pressure of the gas over the solution. P = KHC where P is the partial pressure of the gas above the solution KH is the Henry's Law constant for the solution C is the concentration of the dissolved gas in solution C = P/KH C = 2.4 atm/29.76 atm/(mol/L) C = 0.08 mol/L since we only have 1 L of water, we have 0.08 mol of CO2. Convert moles to grams mass of 1 mol of CO2 = 12+(16x2) = 12+32 = 44 g g of CO2 = mol CO2 x (44 g/mol) g of CO2 = 8.06 x 10-2 mol x 44 g/mol g of CO2 = 3.52 g Answer: There are 3.52 g of CO2 dissolved in a 1 L bottle of carbonated water from the manufacturer.

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